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How to create time windows given start and stop indices

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I have 2 vectors of indices: 1 for start times and 1 for end times:
>> size(trainStarts)
ans =
20 1
>> size(trainEnds)
ans =
20 1
Is there a way to, without using loops, that I can create a new variable representing windows that would be like trainStarts(1) : trainEnds(1), trainStarts(2) : trainEnds(2) and so on?

Accepted Answer

Voss
Voss on 10 Nov 2022
Here's one way:
trainStarts = [2 10 15];
trainEnds = [6 12 21];
result = arrayfun(@(x,y)x:y,trainStarts,trainEnds,'UniformOutput',false)
result = 1×3 cell array
{[2 3 4 5 6]} {[10 11 12]} {[15 16 17 18 19 20 21]}

More Answers (1)

Image Analyst
Image Analyst on 10 Nov 2022
Edited: Image Analyst on 10 Nov 2022
Yes, but why? What's wrong with having them in separate arrays.
for k = 1 : length(trainStarts)
thisRange = trainStarts(k) : trainEnds(k);
% Now do something with thisRange.
end
If you want to store/keep all the ranges separately you need to put them into cells because each range might be a different number of elements.
for k = 1 : length(trainStarts)
thisRange{k} = trainStarts(k) : trainEnds(k);
% Now do something with thisRange.
end
If you don't know what a cell array is see the FAQ:
  2 Comments
Anas Khan
Anas Khan on 10 Nov 2022
Thanks, yeah, I may not need to keep the ranges. I was just trying to keep the code as clean as possible for downstream analysis.
Image Analyst
Image Analyst on 10 Nov 2022
Then use my first snippet rather than my second snippet or the answer you Accepted. No sense storing stuff you don't need to store.

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