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Know the number of row within a structure (struct)

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Hi! I have the following 'CODE' struct.
I would like to know if there is a code to determine the row number (present in 'Fields', for example 7) considering this as input:
folder = 'C:\Users\Alberto\Desktop\GLOBAL\DATA 4'
Stephen23 on 10 Nov 2022
Edited: Stephen23 on 10 Nov 2022
"(present in 'Fields', for example 7)"
The heading is misleading: the column headers are the fieldnames (e.g. "name", etc), the row numbers are indices of elements of the structure array (you can see there are 12 row numbers, exactly matching the number of elements in that 12x1 structure).
Note that "DATA 4" is listed in elements 7, 8, and 9 of that structure array.
Alberto Acri
Alberto Acri on 10 Nov 2022
Edited: Alberto Acri on 10 Nov 2022
@Stephen23 Yes, I know! I wanted to determine element 7 of struct CODE in correspondence of 'name' 'a'.
But the same is true for example at element 1,4,10 of struct CODE at 'name' 'a' where 'DATE 1', 'DATE 11' and 'DATE 6' are given respectively.

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Accepted Answer

Joseph Cheng
Joseph Cheng on 10 Nov 2022
so you can use the function find() and contains(). in this example i am just searching the name entry but it should work with your folder instead.
abc = 'a'-1;
for ind = 1:10
CODE(ind).name = char(abc+ind);
foundRow = find(contains({},'d'))
foundRow = 4
Where by doing {} here it'll make each entry into a cell then find which one contains your desired text.
Stephen23 on 10 Nov 2022
Edited: Stephen23 on 10 Nov 2022
@Alberto Acri: note that Joseph Cheng just used the loop to create some fake data to demonstrate how the code works. Of course you will not use the loop and you will use your own data. Try this to match the names:
foundRows = find(matches({},'d'))
or if you want to match the folders (as your question specifies):
folder = 'C:\Users\Alberto\Desktop\GLOBAL\DATA 4'
foundRows = find(matches({CODE.folder},folder))

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