How do I exit a for loop after logical index is found true in an array?

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I would like to exit a loop if the result is set to true in the for loop. But it always returns false if I use 'continue'. How do I resolve this?
% check if trajectory goes through the zone
result = false;
for i = 1:length(xNormalized)
if (xNormalized(i) > xEdge(1) && xNormalized(i) < xEdge(2)) && ...
(yNormalized(i) > yEdge(1) && yNormalized(i) < yEdge(2))
result = true;
end
% continue;
end

Accepted Answer

VBBV
VBBV on 4 Dec 2022
use inside the if-end statement
% check if trajectory goes through the zone
result = false;
for i = 1:length(xNormalized)
if (xNormalized(i) > xEdge(1) && xNormalized(i) < xEdge(2)) && ...
(yNormalized(i) > yEdge(1) && yNormalized(i) < yEdge(2))
result = true
break % use inside the if - condition
end
end
  2 Comments
Struggling in MATLAB
Struggling in MATLAB on 4 Dec 2022
Thank you! I was using outside the if statement and that did not work. It works if I use inside if as you suggested. By the way, this for loop is the outermost loop.

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More Answers (1)

Steven Lord
Steven Lord on 4 Dec 2022
continue exits the current iteration and proceeds to the next iteration.
break exits the loop entirely.
  1 Comment
Struggling in MATLAB
Struggling in MATLAB on 4 Dec 2022
Both 'break' and 'continue' sets the result to default 'false'. I tried with both of them.

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