# How to convert matrices of different sizes in a for loop into a single column vector?

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Anisia Anil on 5 Dec 2022
Answered: Bruno Luong on 16 Jan 2023
A = im2single(squeeze(mean(A,3)));
A = im2double(A);
[pyrRef,pind] = buildLpyr(A,'auto');
nLevels = 7;
kernelx = [0.0, 0.0, 0.0; 0.5, 0.0, -0.5; 0.0, 0.0, 0.0];
kernely = [0.0, 0.5, 0.0; 0.0, 0.0, 0.0; 0.0, -0.5, 0.0];
for k = 1:nLevels
subband = pyrBand(pyrRef, pind, k);
rx(k) = conv2(subband(k),kernelx);
ry(k) = conv2(subband(k),kernely);
amp = sqrt(subband.^2 + rx(k).^2 + ry(k).^2);
Phase = acos(subband./amp);
end
Here, the value of "Phase" is a matrix with varying dimension at each iteration of 'k'. How do I save all the values in these k matrices into a single coloumn vector?
##### 2 CommentsShowHide 1 older comment
Anisia Anil on 5 Dec 2022
by "save all" I meant, I want to save all k number of matrices into a sigle coloumn vector.

Jan on 5 Dec 2022
...
PhaseC = cell(1, nLevels);
for k = 1:nLevels
...
PhaseC{k} = acos(subband./amp);
end
Phase = cat(2, PhaseC{:}); % Maybe cat(1, ...

MFK on 16 Jan 2023
for k = 1:nLevels
...
Phase = acos(subband./amp);
re_shaped_Phas{k,1}=reshape(Phase,1,[]);
end

Bruno Luong on 16 Jan 2023
...
PhaseC = cell(1, nLevels);
for k = 1:nLevels
...
Phase = acos(subband./amp);
PhaseC{k} = Phase(:);
end
Phase = cat(1, PhaseC{:});