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How can I generate a pseudo random column vector V

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for N = [1 2 5 10.^[ 1 : 5 ] ]
V = rand( N, 1 ) ; % I'm not sure if it should look like this
end
I have this cycle, how can I generate a pseudo random column vector V of varying length N (using this cycle)

Answers (1)

Jon
Jon on 5 Dec 2022
Yes this will make a random column vector of length N at each iteration.
The values will be uniformly distributed between 0 and 1. If you want them normally distributed use randn.
  2 Comments
Jon
Jon on 6 Dec 2022
Glad that helped. If that answered your question please accept the answer so that others who might have a similar problem will know that an answer is available.

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