matrix manipulation

1 view (last 30 days)
Max
Max on 20 Oct 2011
I have a matrix like this
A=[1 1 1 5 5 5 5 7 7 7; 1 1 1 5 5 5 5 7 7 7; 2 2 2 9 9 9 9 3 3 3 ; 2 2 2 9 9 9 9 3 3 3; 2 2 2 9 9 9 9 3 3 3]
i want to segregate the matrix like this
A1=[1 1 1; 1 1 1 ]
A2=[5 5 5 5; 5 5 5 5 ]
A3=[7 7 7 ; 7 7 7]
A4=[2 2 2; 2 2 2 ; 2 2 2 ]
A5=[9 9 9 9; 9 9 9 9; 9 9 9 9]
and so on.. i am not getting any idea /.. kindly help me ..

Answers (2)

David Young
David Young on 20 Oct 2011
A1 = A(1:2, 1:3);
A2 = A(1:2, 4:7);
and so on.

Andrei Bobrov
Andrei Bobrov on 20 Oct 2011
Use a cell array Aout instead of A1, A2 ...
A=[1 1 1 5 5 5 5 7 7 7; 1 1 1 5 5 5 5 7 7 7; 2 2 2 9 9 9 9 3 3 3 ; 2 2 2 9 9 9 9 3 3 3; 2 2 2 9 9 9 9 3 3 3];
[ig1 ig2 c] = unique(A,'first');
icl = struct2cell(regionprops(reshape(c,size(A)), 'PixelList'));
[ig3,idx] = sort(cellfun(@(x)(x(1,2)-1)*size(A,1)+x(1,1),icl));
f = @(x)A(min(x(:,2)):max(x(:,2)),min(x(:,1)):max(x(:,1)));
Aout = cellfun(f,icl(idx),'un',0)
variant
data = regionprops(A,'BoundingBox');
[a b] = unique(A);
idl = cat(1,data.BoundingBox);
idl = idl(all(idl(:,3:4),2),[4 3]);
[ign,idx]= sort(b);
idx2 = reshape(reshape(idx,2,[])',[],1);
a2 = a(idx2);
idl2 = idl(idx2,:);
Aout = arrayfun(@(i1)a2(i1)*ones(idl2(i1,:)),1:numel(a2),'un',0)
small modify
data = regionprops(A,'BoundingBox');
idl = cat(1,data.BoundingBox)
lc = all(idl(:,3:4),2)
idl = ceil(idl(lc,[1 2 4 3]))
num = nonzeros((1:9)'.*lc)
[ign,idx]=sortrows([bsxfun(@minus,idl(:,1:2),[0 1])*[1;size(A,2)],idl(:,3:4)],1)
sz=ign(:,2:end)
num=num(idx)
Aout = arrayfun(@(i1)num(i1)*ones(sz(i1,:)),1:numel(num),'un',0)
small variant
a = unique(A);
m = nonzeros(arrayfun(@(x)histc(A(:,1),x),a))
n = nonzeros(arrayfun(@(x)histc(A(1,:),x),a))
Aout = reshape(mat2cell(A,m,n)',[],1)

Categories

Find more on Matrices and Arrays in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!