Hi Everyone. Ive created a set of questions for user to select the material characteristics based on their preferences and need help to choose best results best on their ans

Below is the coding. i want to show user which material between is the best based on average answer. Kindly need your help.

x=input('enter required strength /10 =');

if x>0 && x<=5

save ('AS')

save ('AA')

elseif x>5 && x<=8

save ('PL')

elseif x>8 && x<=10

save ('PC')

end

t=input('choose hardness 75/80/90/100 =');

if t==75

save('PL')

elseif t==80

save('PC')

elseif t==90

save('AA')

elseif t==100

save('AS')

end

reply=input('enter expected finishing low-med-high : ','s');

if strcmp(reply,'low')

save('AS')

elseif strcmp(reply,'med')

save('PC and PL')

elseif strcmp(reply,'high')

save('AA')

end

[Rik]

What are you expecting to happen with those save calls? What do you want to happen? How would you design the system with pen and paper?

[Muhammad Ammar Fiqri Bin Johari Johari]

Apologize as im new to MATLAB. Previously i subtitutes the save calls by using display calls which shows the answer of selected materials to the user. therefore each of the questions answer will be displaying the type of materials. So out of the few questions answerered by user, i would like to create a code that can shows best answer based on the average selections. However i prefer that each of the answers selected by user was not shown to user as they will only get the final result based on the answer select. i supposed it is as a concept of an expert system.

[Rik]

And how would you solve this with pen and paper? Would you have some sort of points system so at the end you can select the option with the most points?

You need to do something in each branch that you can keep track of. Presumably that is what you intended with the save calls. The save calls resulted in the creation of mat files. What could you replace that with? Based on a set of answers, how do you want to determine the best?

[Muhammad Ammar Fiqri Bin Johari Johari]

Understand that. I can say it can come as a point system. For example out of 3 questions answered by user, if 2 out of 3 of the answer selected is PL and 1 is AS , thus the final result will show that best material is PL and user will see the answers from the final result. If i may ask, what type of code that i can identify for each branch that can support such arrangement? Appreciate your help.

Answer 1

[Karim]

Hi, see below for some possibilities on how to code such selection.

% material options
Materials = ["AS";"AA";"PL";"PC"];

Strength = zeros(numel(Materials),1);
Hardness = zeros(numel(Materials),1);
Finishing = zeros(numel(Materials),1);

SelectionTable = table(Materials,Strength,Hardness,Finishing);

% get user input
% Strength = input('enter required strength /10 =');
% Hardness = input('choose hardness 75/80/90/100 =');
% Finishing = input('enter expected finishing low-med-high : ','s');

% user inputs is not possible online, hence pick some random results:
Strength = 4;
Hardness = 80;
Finishing = 'med';

% logic for the strength
if Strength>0 && Strength<=5
    SelectionTable.Strength([1,2]) = 1;
elseif Strength>5 && x<=Strength
    SelectionTable.Strength(3) = 1;
elseif Strength>8 && Strength<=10
    SelectionTable.Strength(4) = 1;
end

switch Hardness
    case 75;  SelectionTable.Hardness(3) = 1;
    case 80;  SelectionTable.Hardness(4) = 1;
    case 90;  SelectionTable.Hardness(2) = 1;
    case 100; SelectionTable.Hardness(1) = 1;
end

switch lower(Finishing)
    case 'low';  SelectionTable.Finishing(1) = 1;
    case 'med';  SelectionTable.Finishing([3,4]) = 1;
    case 'high'; SelectionTable.Finishing(2) = 1;
end

% print the final selection table, this gives an overview of the material
% possibilities based on the user choises and the selection logic
SelectionTable

SelectionTable = 4×4 table
    Materials    Strength    Hardness    Finishing
    _________    ________    ________    _________

      "AS"          1           0            0    
      "AA"          1           0            0    
      "PL"          0           0            1    
      "PC"          0           1            1    

% to make a suggestion, we could pick the material that has the most 1's:
Suggestion = sum(SelectionTable{:,2:end},2)

Suggestion = 4×1

1 1 1 2

[~,materialIdx] = max(Suggestion)

materialIdx = 4

fprintf('Based on the user inputs, the recommended material is %s \n',SelectionTable{materialIdx,1})

Based on the user inputs, the recommended material is PC 

[Muhammad Ammar Fiqri Bin Johari Johari]

Thank You for your information. Its what i required for my current coding arrangement. Appreciate your help