Fitting Numerical Solution of PDE to Given Data with Multiple Parameters
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I'm trying to fit my solution to be as close as possible to given data for my PDE system. I've been using the following as a reference (https://www.mathworks.com/matlabcentral/answers/406938-fitting-the-numerical-solution-of-a-pde-with-one-parameter-to-some-data) which has been super helpful. I was able to reproduce the results from the example (shown below), and I've adapted the code to my PDE system (which I'm solving for 10 parameters instead of one).
But as I run my code, the parameters are not adjusting at all, and it produce the following result.

As the message said, I adjusted the step tolerance to be lower (10^(-10)) so that it may continue find the optimal parameters. But as its being solved, the parameters don't adjust from the initialized ones. Is there a possible explanation and a remedy for this issue?
(Note: I'll provide my code as a comment to this question post. But of course, I won't be able to provide the data I'm using to compare to train the optimization algorithim )
global exper
exper=[-0.4,-112,-121,-128,-131,-131.1,-133.2,-133.1,-134.4,-134.7,-135.12,-135.7,-135.8,-135.1,-135.4,-135.8,-135.9,-134,-135.7,-135.1,-135.3,-135.4,-136,-139,-136];
% p=[0.218,0.52,0.0115,2.03,31.6];
% qr f a n ks
p0=[0.218,0.52,0.0115,2.03,31.6];
lb=[0.01,0.4,0,1,15]; %lower bound
ub=[Inf,Inf,10,10,100]; %upper bound
options = optimoptions('lsqnonlin','Algorithm','trust-region-reflective','Display','iter');
[p,resnorm,residual,exitflag,output] = lsqnonlin(@richards1,p0,lb,ub,options)
uu=richards1(p);
global t
plot(t,uu+exper')
hold on
plot(t,exper,'ko')
function uu=richards1(p)
% Solution of the Richards equation
% using MATLAB pdepe
%
% $Ekkehard Holzbecher $Date: 2006/07/13 $
%
% Soil data for Guelph Loam (Hornberger and Wiberg, 2005)
% m-file based partially on a first version by Janek Greskowiak
%--------------------------------------------------------------------------
L = 200; % length [L]
s1 = 0.5; % infiltration velocity [L/T]
s2 = 0; % bottom suction head [L]
T = 4; % maximum time [T]
% qr = 0.218; % residual water content
% f = 0.52; % porosity
% a = 0.0115; % van Genuchten parameter [1/L]
% n = 2.03; % van Genuchten parameter
% ks = 31.6; % saturated conductivity [L/T]
x = linspace(0,L,100);
global t
t = linspace(0,T,25);
options=odeset('RelTol',1e-4,'AbsTol',1e-4,'NormControl','off','InitialStep',1e-7)
u = pdepe(0,@unsatpde,@unsatic,@unsatbc,x,t,options,s1,s2,p);
global exper
uu=u(:,1,1)-exper';
% figure;
% title('Richards Equation Numerical Solution, computed with 100 mesh points');
% subplot (1,3,1);
% plot (x,u(1:length(t),:));
% xlabel('Depth [L]');
% ylabel('Pressure Head [L]');
% subplot (1,3,2);
% plot (x,u(1:length(t),:)-(x'*ones(1,length(t)))');
% xlabel('Depth [L]');
% ylabel('Hydraulic Head [L]');
% for j=1:length(t)
% for i=1:length(x)
% [q(j,i),k(j,i),c(j,i)]=sedprop(u(j,i),p);
% end
% end
%
% subplot (1,3,3);
% plot (x,q(1:length(t),:)*100)
% xlabel('Depth [L]');
% ylabel('Water Content [%]');
% -------------------------------------------------------------------------
function [c,f,s] = unsatpde(x,t,u,DuDx,s1,s2,p)
[q,k,c] = sedprop(u,p);
f = k.*DuDx-k;
s = 0;
end
% -------------------------------------------------------------------------
function u0 = unsatic(x,s1,s2,p)
u0 = -200+x;
if x < 10 u0 = -0.5; end
end
% -------------------------------------------------------------------------
function [pl,ql,pr,qr] = unsatbc(xl,ul,xr,ur,t,s1,s2,p)
pl = s1;
ql = 1;
pr = ur(1)-s2;
qr = 0;
end
%------------------- soil hydraulic properties ----------------------------
function [q,k,c] = sedprop(u,p)
qr = p(1); % residual water content
f = p(2); % porosity
a = p(3); % van Genuchten parameter [1/L]
n = p(4); % van Genuchten parameter
ks = p(5); % saturated conductivity [L/T]
m = 1-1/n;
if u >= 0
c=1e-20;
k=ks;
q=f;
else
q=qr+(f-qr)*(1+(-a*u)^n)^-m;
c=((f-qr)*n*m*a*(-a*u)^(n-1))/((1+(-a*u)^n)^(m+1))+1.e-20;
k=ks*((q-qr)/(f-qr))^0.5*(1-(1-((q-qr)/(f-qr))^(1/m))^m)^2;
end
end
end
1 Comment
Thomas Rodriguez
on 31 Dec 2022
Answers (0)
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