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parfor unable to classify, why?

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Bruno Luong
Bruno Luong on 4 Jan 2023
Commented: Edric Ellis on 5 Jan 2023
Can someone explain why the ind2sub first statement triggers the error, but the second works fine?
m = 2;
n = 3;
mycell = cell(m,n);
parfor k = 1:numel(mycell)
[i,j] = ind2sub(size(mycell), k); % MATLAB complains cannot classify mycell because of this
%[i,j] = ind2sub([m n], k); % this iis however accepted
mycell{k} = 1;
end
Error: Unable to classify the variable 'mycell' in the body of the parfor-loop. For more information, see Parallel for Loops in MATLAB, "Solve Variable Classification Issues in parfor-Loops".

Accepted Answer

Matt J
Matt J on 4 Jan 2023
Edited: Matt J on 4 Jan 2023
I suspect it is because mycell is intended to be a sliced variable, but the code violates the fixed indexing rule,
Fixed Index Listing. Within the first-level indexing of a sliced variable, the list of indices is the same for all occurrences of a given variable.
since in one place you index mycell with {k} and elsewhere you do not index it at all. Notice that this also doesn't work:
m = 2;
n = 3;
mycell = cell(m,n);
parfor k = 1:numel(mycell)
mycell;
mycell{k} = 1;
end
I also vaguely wonder if it makes sense for a parpool worker to try to determine the size() of a sliced variable when it only receives a piece of it.
  5 Comments
Matt J
Matt J on 5 Jan 2023
Edited: Matt J on 5 Jan 2023
@Edric Ellis If mycell were sliced, is it even possible for a parpool worker to determine its original size? Putting it another way, does a sliced variable somehow carry the metadata of the original, unsliced variable?
Edric Ellis
Edric Ellis on 5 Jan 2023
@Matt J no, the sliced portion on the worker doesn't directly know the metadata of the original array (but the code running on the worker does know enough to make sure it writes the correct piece of the sliced portion that it is working with) - this is just one reason why it's not valid to attempt to access the "whole" variable in any way in the body of the loop.

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