How to shuffle numbers for each iteration?

I am having 'n' randomnly generated positive decimal number. With this input I have performed some set of mathematical calculations. Now i need to repeat the mathematical calculations with changed order of decimal number and this has to be followed for each iteration until a certain condition is met.

Example:

A= 5, 2, 4, 3, 7, 1, 6

Expected output: Shuffle decimal number for each iteration. [only positive number is required]

[Jiri Hajek]

Hi, your question is not very clear. Do you need to permute digits in a number?

[Dyuman Joshi]

Do you need the numbers 1 to 7 in a (different) random order for each iteration?

[ASHA PON]

Yes. I need numbers 1 to 7 in different order for each iteration. Thank you

[Dyuman Joshi]

Try randperm -

Or if you want all permutations in once, and then loop through them, check out perms()

n=7;
iter=10;
for idx=1:iter
    randperm(n)
end

ans = 1×7

6 7 2 3 1 4 5

ans = 1×7

3 7 5 1 6 2 4

ans = 1×7

2 5 6 7 4 3 1

ans = 1×7

1 6 5 2 3 7 4

ans = 1×7

7 4 2 5 6 1 3

ans = 1×7

4 3 7 5 6 2 1

ans = 1×7

1 5 7 2 3 4 6

ans = 1×7

1 5 7 4 3 2 6

ans = 1×7

6 4 7 1 2 5 3

ans = 1×7

7 6 2 1 5 4 3

[ASHA PON]

Thank you. This is what i expected

[ASHA PON]

Hello Dyuman joshi. The code you have suggested works very well, when it is applied seperately. But while i use this same code and apply some calculation after randperm(n), I didn't get different decimal numbers for each iteration. Can you please guide me where I am making mistake. Thank you.

[Dyuman Joshi]

Can you show your code? Without the code, it is difficult to tell where the problem is.

Answer 1

[Tobias]

It seems you try to do something like a minmum search. Probably, you can solve the origin problem in a more target oriented way.

For your question to shuffle a vector you could do something like this:

Expect having a vector with several digits. In this example 1 to 7:

vector = 1:7;

For example, you could shuffle it like this:

vector = vector(randperm(length(vector)));