# closest value to zero excluding the first one?

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Ali Almakhmari on 12 Jan 2023
Commented: Bruno Luong on 12 Jan 2023
If given a long vector of values. How can I find the index of the closest value to zero excluding the first value of the vector out of our list of stuff to search for
Ali Almakhmari on 12 Jan 2023
I am attaching an example variable and the answer your code should result in should be 175 or the 174 index.
Ali Almakhmari on 12 Jan 2023
I = find(diff(dis_y>=0),1);

Ali Almakhmari on 12 Jan 2023
"dis_y" being the variable:
I = find(diff(dis_y>=0),1);
Bruno Luong on 12 Jan 2023
That is NOT your question asks for, that is first consecutive points where 0 is cross from positive to negative.

Torsten on 12 Jan 2023
Edited: Torsten on 12 Jan 2023
out of our list of stuff to search for
?
v = [-0.1 2 4 -0.5 8];
[~,i] = min(abs(v(2:end)))
i = 3
v(i+1)
ans = -0.5000
##### 3 CommentsShow 1 older commentHide 1 older comment
Ali Almakhmari on 12 Jan 2023
Edited: Ali Almakhmari on 12 Jan 2023
hmm I dont think this works. For example, I attached this variable here. The answer to my question should be 175 or the 174 index. But with this code you have I do not get that.
Ali Almakhmari on 12 Jan 2023
Actually I found the solution: I = find(diff(dis_y>=0),1);

Bora Eryilmaz on 12 Jan 2023
Edited: Bora Eryilmaz on 12 Jan 2023
[~,I] = sort(abs(dis_y), 'ascend');
% Closest value to 0:
dis_y(I(1))
ans = 2.3761e-05
% Second closest value to 0:
dis_y(I(2))
ans = -0.0014
Ali Almakhmari on 12 Jan 2023
This is still not giving me 175 or 174.
Ali Almakhmari on 12 Jan 2023
I = find(diff(dis_y>=0),1);

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