Can I run all cases of switch ? if not, is there another way ?
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The attached code is running only one of the cases randomly. My question Can I execute all cases in random way, for example run the third loop (case 3) then the first loop (case 1) and after that the second loop (case 2 ) and then iterate the MAIN LOOP as shown below. If that can't be done, I appreciate another way if its possible.
Thanks in advance
for q=1:5 % MAIN LOOP
t = randperm(3,1);
switch t
case 1
for q1=1:10 % Loop 1
disp(1);
end
case 2
for q2=1:10 % Loop 2
disp(2);
end
case 3
for q3=1:10 % Loop 3
disp(3);
end
end
end
0 Comments
Accepted Answer
dpb
on 21 Feb 2023
Edited: dpb
on 21 Feb 2023
That's just putting the switch block inside another loop...
...
M=5; % outer loop counter
N=3; % number switch blocks
for q=1:M % MAIN LOOP
for t=randperm(N) % execute the |switch| randomly in sequence for all cases
switch t
case 1
for q1=1:10 % Loop 1
disp(1);
end
case 2
for q2=1:10 % Loop 2
disp(2);
end
case 3
for q3=1:10 % Loop 3
disp(3);
end
end
end
end
The above will do all cases in random order each time with no repeats; one could choose alternate sampling patterns as well, of course of "N of K" or even not require no replications.
6 Comments
dpb
on 21 Feb 2023
See patched Answer/Comment above...
N=3;
for i=1:2
fprintf('i: %d\n',i)
for t=randperm(N)
disp(t)
end
end
More Answers (1)
Walter Roberson
on 21 Feb 2023
Edited: Walter Roberson
on 22 Feb 2023
I already gave you code that permits you to exactly control the minimum number of times each of the cases is to be executed (in a random order), with any remaining iterations to be chosen at random.
2 Comments
dpb
on 21 Feb 2023
Hadn't realized you'd already solved it, Walter. This was first I saw OP's plea...
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