Please how can I calculate the values of this finite sum of numbers in fully sequential , I'm finding it difficult

Answer 1

[Antoni Garcia-Herreros]

Hello,

You can try something like this:

n=1000; %Specify your n
SUM=zeros(n,1);
for i=1:n;
    SUM(i)=1./i^4;
end
value=sum(SUM); %This is the result of your sum 

[Torsten]

@Antoni Garcia-Herreros

Why do you name the summands of the series "SUM" ? That's quite misleading.

[Lateef]

@Torsten

Please how would you go about it?

[Torsten]

What do you mean by "sequential" in your question ? You mean you want to compute all partial sums up to a specified n ? Or - as @Antoni Garcia-Herreros did correctly - only evaluate the sum for a specified value of n ?

[Walter Roberson]

My guess is that they need to use a "for" or "while" loop, rather than a formula.

[Lateef]

i have been able to get it done in fully sequential

i need help in implementing it for distribued using a parfor loop for different processors

[Lateef]

im finding it hard to illustrate my equation in the parfor loop correctly

[Lateef]

@Walter Roberson

[Walter Roberson]

n=1000; %Specify your n
SUM=zeros(n,1);
parfor i=1:n;
    SUM(i)=1./i^4;
end
value=sum(SUM); %This is the result of your sum 

Answer 2

[John D'Errico]

Easy peasy.

sumof4thpowers = @(N) nchoosek(N+1,5) + 11*nchoosek(N+2,5) + 11*nchoosek(N+3,5) + nchoosek(N+4,5);

For example:

sumof4thpowers(4)

ans = 354

Was it correct?

1^4 + 2^4 + 3^4 + 4^4

ans = 354

Note that you asked only how to compute the sum, not how to derive the expresssion I gave. But they can be shown to be equivalent.

[Lateef]

how do i compute the expresssion on mathlab for n= 1000000

[Torsten]

By setting the sum to pi^4/90.

Answer 3

[Walter Roberson]

Example:

syms i n

symsum(i^(-7), i, 1, n)

ans = 

char(ans)

ans = 'zeta(7) + psi(6, n + 1)/720'