How to include NaN elements in an array based on a condition?
2 views (last 30 days)
Show older comments
Annapurna Mandalika
on 30 Mar 2023
Edited: Davide Masiello
on 30 Mar 2023
Can someone help me out in writing a code to insert NaN eleemnts in an array if the element is not a consecutive multiple of 2? For example if a = [2 4 6 12 14 18]; Im expecting to be turned out as a = [2 4 6 NaN NaN 12 14 NaN 18]; Thank you
0 Comments
Accepted Answer
Davide Masiello
on 30 Mar 2023
Edited: Davide Masiello
on 30 Mar 2023
a = [2 4 6 12 14 18];
A = a(1):2:a(end);
new_a = zeros(size(A));
idx = any(a'== A,1);
new_a(idx) = a;
new_a(~idx) = nan;
new_a
0 Comments
More Answers (0)
See Also
Categories
Find more on Logical in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!