how to calculate this equation in matlab?

for i, n >3

can i calulate or generate any program for this equation.

[VM Sreeram]

Seems to be a homework question. Read this answer to know more.

[John D'Errico]

Sure. you CAN calculate it. You could start with the known sum of a geometric series, for the internal sum on the powers of 2.

And then you could use a simple loop to compute that product. Or, you could create a vector of elements, and then use prod.

But, since this is probably homework, and you have made no attempt at all, you should start writing. Make an effort, and you would get more help. Make no effort at all, and we tell you to learn MATLAB, and to make an effort.

[Torsten]

Since the upper limit of the product is 3 and i is assumed to be greater than 3, the product is empty. By convention, its value is 1. Thus the result of your expression is n*(n-1)*(n-2)*1/2.

[Kajal Agrawal]

ok, i have tried with loop but doesn't work properly.

[Dyuman Joshi]

Please show what you have attempted.

[Kajal Agrawal]

I think i have mistaken in loop..

Answer 1

[Harsh Kumar]

Hi Kajal ,

It is my understanding that you are interested in generating a program for the above mentioned mathematical equation.

You can use the concept of 'Nested Loop' to iterate over the two variables i.e, r and j for addition and multiplication respectively.

Please refer to the below code snippet for better understanding.

clc 
clear 
n=input('enter the value of n=')
i=input('enter the value of i=')
 %variable to store product of terms
p=1;
for j=i:3
   s=0;   %sum variable 
  for r=1:j-2
    s=s+(2^(j-2-r));
    p=prod(p,2^(j-2)*(n)-(2^(j-1)-s));
  end 
end
vertices=(n*(n-1)*(n-2)*p)/2;
disp('vertices')
vertices