Clear Filters
Clear Filters

How can i plot a line from an already plotted line?

1 view (last 30 days)
I'm doing a code for brake study and, I've been trying to add a proportioning valve to my code. It essencialy creates a line in the optimum cuve graph. It is similar to this green curve:
Does anyone know how to adjust the starting point of the green line, so it starts from any poiny at the black line? Here is the method I used for this graph:
p2(32) = plot(ar_VC(find(ax_VC==ak):end),af_VC(find(ax_VC==ak):end),'-','Color', 1/255*[70,250,120],'LineWidth',3);
  4 Comments
Rodrigo
Rodrigo on 3 Aug 2023
Edited: Rodrigo on 3 Aug 2023
i want to translate the green line to a starting point where it stars anywhere on the black line.
And the black line was plotted like the code below, it´s a bunch of books which resulted on the black line.
p2(30) = plot(ar_4x2,af_4x2,'-','Color',1/255*[0,0,0],'LineWidth',3);
Sam Chak
Sam Chak on 3 Aug 2023
@Rodrigo, If you have a starting point (pivot) fixed on the black line, then the green line projected from the pivot, looks like rotated about the pivot relative to the black line.

Sign in to comment.

Answers (1)

Daniel Bengtson
Daniel Bengtson on 3 Aug 2023
% for a given value of X that lands on the defined range of the black line,
% define the corresponding Y value
X = 5;
blackX = ar_4x2;
blackY = af_4x2;
greenX = ar_VC(find(ax_VC==ak):end);
greenY = af_VC(find(ax_VC==ak):end);
% create first order fit of black line to allow for arbitrary X input
p = polyfit(blackX,blackY,1);
Y = polyval(p,X);
% shift green X and Y based on the difference between green(1) and black(1)
% then account for the translation along the black line
greenX = greenX - (greenX(1) - blackX(1)) + X;
greenY = greenY - (greenY(1) - blackY(1)) + Y;
figure;
p2(30) = plot(blackX,blackY,'-','Color',1/255*[0,0,0],'LineWidth',3);
hold on
p2(32) = plot(greenX,greenY,'-','Color', 1/255*[70,250,120],'LineWidth',3);

Categories

Find more on 2-D and 3-D Plots in Help Center and File Exchange

Tags

Products


Release

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!