How to deduct obtained fuel value from initial weight
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Hi, the following code is the initial calculation, I have obtained the fuel consumed to climb at each altitude (53 x 1 results) (the final code), I want to deduct this fuel consumption from the weight at every altitude (the weight is denoted is W) because weight reduced as the aircraft fly. 
May I know how do I code it? I heard can use for-loop with different iteration? (because I have used a for-loop for other calculation before getting onto the coding below)
Please help. Very much appreciate :)
%% Coefficient of Lift
CDO = 0.023; % Zero-lift drag coefficient
K = 0.044; % Lift-induced drag factor
MTOW =  79010; % Maximum take-off mass [kg]
W = MTOW*9.81; % Weight in N
A= Thrust_22K/W;
B = sqrt((A.^2)+(12*CDO*K));
Cl = (6*CDO)./(A+B);
%% Drag Produced 
S = 125; % Wing area [m^2]
C = CDO + (K*(Cl.^2));
D = 0.5*Density_altitude.*(TAS.^2)*S.*C; % [N]
%% Power Available
P_available = TAS.*Thrust_22K;
%% Power Required
P_required = TAS.*D;
%% Excess Power 
P_excess = P_available - P_required; 
%% Rate of Climb (ROC)
ROC = (TAS.*(Thrust_22K - D))./W; % [m/s]
if any(ROC <=1.5)
    disp('Service Ceiling.')
else 
    disp ('Absolute Ceiling.')
end 
%% Climb Angle 
X = (Thrust_22K - D)./W;
Climb_angle = asind( X ); % [Degree]
%% Time Taken to Climb 
Time = Altitude./ROC; % [sec]
%% Mass Flow Rate
m_dot_f = TSFC_22K.*Thrust_22K; % [kg/s]
%% Fuel Consumed to Climb 
Fuel = m_dot_f.*Time;
5 Comments
  William Rose
      
 on 21 Sep 2023
				
      Edited: William Rose
      
 on 21 Sep 2023
  
			As @Dyuman Joshi pointed out, it is not clear what quantities are vectors and what quatities are scalars. 
  Dyuman Joshi
      
      
 on 21 Sep 2023
				It will be better if you can attach your whole code including values for variables, as has been mentioned before.
Accepted Answer
  Torsten
      
      
 on 21 Sep 2023
        
      Edited: Torsten
      
      
 on 21 Sep 2023
  
      Most probably something like this. I don't know where you use some of the defined variables - they seem to be superfluous.
%% Coefficient of Lift
CDO = 0.023; % Zero-lift drag coefficient
K = 0.044; % Lift-induced drag factor
W(1) = MTOW*9.81; % Weight in N;
Time(1) = 0.0;
Fuel(1) = 0.0;
for i = 1:numel(Altitude)-1
  A = Thrust_22K/W(i);
  B = sqrt((A.^2)+(12*CDO*K));
  Cl = (6*CDO)./(A+B);
  %% Drag Produced 
  S = 125; % Wing area [m^2]
  C = CDO + (K*(Cl.^2));
  D = 0.5*(Density_altitude(i)+Density_altitude(i+1))/2.*(TAS.^2)*S.*C; % [N]
  %% Power Available
  P_available = TAS.*Thrust_22K;
  %% Power Required
  P_required = TAS.*D;
  %% Excess Power 
  P_excess = P_available - P_required; 
  %% Rate of Climb (ROC)
  ROC = (TAS.*(Thrust_22K - D))./W(i); % [m/s]
  if any(ROC <=1.5)
    disp('Service Ceiling.')
  else 
    disp ('Absolute Ceiling.')
  end 
  %% Climb Angle 
  X = (Thrust_22K - D)./W(i);
  Climb_angle = asind( X ); % [Degree]
  %% Time Taken to Climb 
  Time(i+1) = (Altitude(i+1)-Altitude(i))./ROC; % [sec]
  %% Mass Flow Rate
  m_dot_f = TSFC_22K.*Thrust_22K; % [kg/s]
  %% Fuel Consumed to Climb 
  Fuel(i+1) = m_dot_f.*Time(i+1);
  W(i+1) = W(i) - Fuel(i+1);
end
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