How would I plot this and then achieve minimum and maximum.

This is the equation
My script looks like this and fails
x=0:0.1:15
y=(x)^3/3-11(x)^2/2+24x
plot(x,y)
Not yet got my head around MatlB

 Accepted Answer

x = 0:0.1:15;
% y=(x)^3/3-11(x)^2/2+24x << you were missing multiplication operators *
% and the powers need to be .^ (element-wise operator) instead of ^ (matrix
% operator)
y = x.^3 / 3 - 11*x.^2 / 2 + 24*x;
plot(x, y)
grid on
xlabel x
ylabel y
fprintf('min(y) = %f; max(y) = %f\n', min(y), max(y))
min(y) = 0.000000; max(y) = 247.500000
Also, if you are just getting started with Matlab, I would highly recommend that you take a couple of hours to go through the free online tutorial: Matlab Onramp

2 Comments

Thanks, that OnRamp is really well setup!
That's good to hear. I hope it was helpful.

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More Answers (1)

Hi @Tom
The cubic function does not have global extrema, but it does have a local maximum point and a local minimum point. Are you looking to plot something similar to this?
%% Find local max and local min over a certain range
y = @(x) x.^3/3 - 11*x.^2/2 + 24*x;
xlocal = linspace(1, 10, 90001);
ymax = max(y(xlocal))
ymax = 31.5000
idx1 = find(y(xlocal) == ymax);
xmax = xlocal(idx1)
xmax = 3
ymin = min(y(xlocal))
ymin = 10.6667
idx2 = find(y(xlocal) == ymin);
xmin = xlocal(idx2)
xmin = 8
%% Plot function over a predefined range
x = 0:0.1:15;
plot(x, y(x)), grid on, hold on
plot(xmax, ymax, 'o', 'markersize', 12, 'linewidth', 2)
plot(xmin, ymin, 'o', 'markersize', 12, 'linewidth', 2)
xlabel('x'), ylabel('y')
xt = [xmax-1 xmin-1];
yt = [ymax+15 ymin+15];
str = {'local max','local min'};
text(xt, yt, str)

2 Comments

I'm a curious as to why you chose to use max() and min() instead of islocalmax() and islocalmin().
Sometimes, I'm accustomed to using functions with the same name in other software. It's good that you introduced islocalmax() and islocalmin().

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Asked:

Tom
on 21 Nov 2023

Commented:

on 24 Nov 2023

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