How can I rotate the axes' labels parallel to the orientation of the axes?

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Hi. I would like to know how to rotate labels and keep them centered with their orientation. Please see Fig 1. This figure is the default view output using the following syntax.
xlabel('x','Rotation',35)
ylabel('y','Rotation',-35)
However, in Fig 2, the plot view is set to:
view([73 24])
Is there a solution to rotate the labels parallel to the orientation of the axes by changing the view values? In this case, the 'Rotation' value (in this example, 35 and -35) changes as a function of the 'View' value (i.e., 73 and 24). Thank you so much for your time and consideration.
[X,Y,Z] = peaks(25);
figure
subplot(1,2,1)
surf(X,Y,Z);
xlabel('x','Rotation',35)
ylabel('y','Rotation',-35)
zlabel('z')
title('Fig.1')
subplot(1,2,2)
surf(X,Y,Z);
xlabel('x')
ylabel('y')
zlabel('z')
view([73 24])
title('Fig.2')

Accepted Answer

Bruno Luong
Bruno Luong on 24 Nov 2023
Edited: Bruno Luong on 24 Nov 2023
Try this (the letters of label are rotated but the aspect ratio remain constant so they can be read easily but are not look like "projected" on the xy plane)
The angles depend on figure/axes aspect ratio, so if you resize them you have to compute the angle again.
[X,Y,Z] = peaks(25);
fig = figure(1);
clf(fig);
t = tiledlayout(2,2);
for k = 1:prod(t.GridSize)
ax = nexttile(t);
surf(ax, X, Y, Z);
%axis(ax, 'equal')
view(ax, rand*360, 40); % random azimuth
set(ax,'unit','pixel');
axPosition = ax.Position;
dx = axPosition(3);
dy = axPosition(4);
[xx, xy] = ScreenProjection(ax, xlim(ax), [0 0], [0 0]);
thetax = atan(diff(xy)/diff(xx)*dy/dx);
xlabel('here is the x-label', 'Rotation', rad2deg(thetax))
[xx, xy] = ScreenProjection(ax, [0 0], ylim(ax), [0 0]);
thetay = atan(diff(xy)/diff(xx)*dy/dx);
ylabel('here is the y-label', 'Rotation', rad2deg(thetay))
zlabel('z')
end
% https://www.mathworks.com/matlabcentral/answers/430790-how-can-i-get-the-screen-coordinates-from-perspective-projection?s_tid=srchtitle
function [xcam, ycam] = ScreenProjection(ax, X, Y, Z)
dataRatio = get(ax, 'DataAspectRatio');
matrixRescale = diag(1./dataRatio);
CT = get(ax,'CameraTarget');
CP = get(ax,'CameraPosition');
CU = get(ax,'CameraUpVector');
cadeg = get(ax,'CameraViewAngle');
CT = CT(:);
CP = CP(:);
CU = CU(:);
ca = cadeg*pi/180;
%
c = CT-CP;
d = norm(c);
c = c / d;
u = CU - dot(c, CU)*c;
u = u/norm(u);
p = cross(c,u);
R=[c,p,u];
XYZ = [X(:),Y(:),Z(:)]';
CPU = R'*(matrixRescale*(XYZ-CP));
XYcam = CPU(2:3,:)./CPU(1,:);
xcam = XYcam(1,:);
ycam = XYcam(2,:);
end
  9 Comments
Bruno Luong
Bruno Luong on 28 Nov 2023
Disapointly the authority's answer of this thread explains the reason of the flaw and unable to suggest a satisfactition way to center label to axe position, beside "do it manually".
When I have time I'll make a code to position and center the labels.
Navid
Navid on 28 Nov 2023
Thank you very much for your kindness and for taking the time to help me. Your assistance is greatly appreciated.

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