Help with iterations over large file.
9 views (last 30 days)
Show older comments
gero pulido
on 11 Dec 2023
Commented: Dyuman Joshi
on 12 Dec 2023
Hello everyone, I have a huge ascii.txt wind file with the following format.
time = 0 hour
2 3 4 5 6 7
0 9 8 7 6 5
7 6 5 4 3 2
9 8 7 6 5 4
time = 3 hour
2 3 4 5 6 7
0 9 8 7 6 5
7 6 5 4 3 2
9 8 7 6 5 4
The thing is that I need to flip the rows from each block between hours, like this
time = 0 hour
9 8 7 6 5 4
7 6 5 4 3 2
0 9 8 7 6 5
2 3 4 5 6 7
time = 3 hour
9 8 7 6 5 4
7 6 5 4 3 2
0 9 8 7 6 5
2 3 4 5 6 7
I can do this for one block by
X = readlines('xwind.txt');
Y = X(2:5);
Y = flip(Y);
But I couldn’t write the loop for the entire file (4865x1 string).
Any help would be much appreciated.
0 Comments
Accepted Answer
Dyuman Joshi
on 11 Dec 2023
If the format of the data is homogenous through the file, try this -
in = readlines('ascii.txt')
for k=2:5:size(in,1)
in(k:k+3,:) = flipud(in(k:k+3,:));
end
in
2 Comments
More Answers (1)
Mathieu NOE
on 11 Dec 2023
hello
try this
I choosed to store each Y array into a cell
D=readlines('data.txt'); % read as string array
[eof] = size(D,1); % last row number (end of file)
ixP1=find(contains(D,'time')); % find the "time" line
ixP1=[ixP1 ; eof]; % add end of file line number
for k=1:numel(ixP1)-1
ind = ixP1(k)+1:ixP1(k+1)-1;
Y = str2num(char(D(ind)));
Y = flip(Y);
out{k} = Y; % store Y flipped in cell array
end
0 Comments
See Also
Categories
Find more on File Operations in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!