Square root symbol does not display using displayFormula function

I had added an * symbol to my string to make the equation more readable after the numbers have been inserted (see picture below). I want the square root symbol to be displayed not sqrt. See the picture below. Maybe there is a better way to add the * symbol so the square root symbol will be displayed.

%Given:

u=symunit;
%Variable-precision arithmetic
capacitance = vpa(2e-6);
displayFormula(["'Given capacitance: '","C = capacitance*u.F"])
displayFormula(["'Given intial charge: '","  ","Q = Q_o"])
resistance = 10.0;
displayFormula(["'Given resistance: '","R = resistance*u.Ohm"])
resistor_dissipated_energy = vpa(0.0036);
displayFormula(["'Given resistor dissipated energy: '","w_R = resistor_dissipated_energy*u.J"])

%Solution:

disp("charge [Q] = capacitance [C] * voltage [V]")
disp("energy [w] = charge [Q] * voltage [V]")
displayFormula(["'Capacitor energy: '","w_C=(1/2)*C*V^2*u.J"])
disp("Rearrange charge equation and solve for V")
displayFormula(["'Voltage: '","V = Q/C"])
disp("Substitute rearranged equation into capacitor energy equation")
displayFormula(["'Capacitor Energy (subsitution): '","w_C=(1/2)*C*(Q/C)^2"])
S = "w_C=(1/2)*(Q^2/C)";
symstr = ["'Capacitor Energy:'","w_C=(1/2)*(Q^2/C)"];
displayFormula(["'Capacitor Energy (simplified): '","w_C=(1/2)*(Q^2/C)"])
disp("Rearrange capacitor energy equation and solver for charge [Q]")
displayFormula(["'Capacitor intial charge: '","Q_o=sqrt(2*w_c*C)"])
%build the string like this to display the * symbol
%not working here
S = ["Q_o=sqrt","'('","'2'","'*'","resistor_dissipated_energy","'*'","capacitance","')'"];
symstr = ["'Capacitor initial charge:'","  ",S];
displayFormula(symstr)
%end of not working
capacitor_intial_charge=sqrt(2*resistor_dissipated_energy*capacitance)*10^6*u.uJ;
displayFormula(["'Capacitor intial charge: '","Q_o = capacitor_intial_charge"])

[Paul]

Hi David,

I don't have a solution. But I am curious how your result shows that 2.0e-6.

resistor_dissipated_energy = vpa(0.0036);
capacitance = vpa(2e-6)

capacitance = 

0.0000019999999999999999094962236517725

displayFormula("capacitance")

0.0000019999999999999999094962236517725

S = "Q_o = sqrt(2*resistor_dissipated_energy*capacitance)"

S = "Q_o = sqrt(2*resistor_dissipated_energy*capacitance)"

displayFormula(S)

How does your result display 2.0e-6?

Answer 1

[Walter Roberson]

S = ["Q_o=sqrt","'('","'2'","'*'","resistor_dissipated_energy","'*'","capacitance","')'"];
symstr = ["'Capacitor initial charge:'","  ",S];
symstr

symstr = 1×10 string array
    "'Capacitor initial…"    "  "    "Q_o=sqrt"    "'('"    "'2'"    "'*'"    "resistor_dissipate…"    "'*'"    "capacitance"    "')'"

displayFormula(symstr)

You broke up the sqrt() across several string parts. Each string part is processed seperately.