how to use an integral function inside a for loop? i need to find the value of function that chages as i chages .then using this values i need to find another integral.

3 views (last 30 days)
r0 =0.1
u =[1:7]'
Q =zeros(length(u),1)
E =zeros(length(Q),1)
for i =1:length(u)
Q(i,1) =0.023*(r0^(-1/4))*((u(i))^(-14/4))
f =@(Q) (Q(i)).^(0.3)
E(i,1) =integral(f,1,7)
end
  3 Comments
Aparna Sekhar
Aparna Sekhar on 5 Jun 2024
Hi Thank you for your respone.Im new to matlab so there may be many mistakes
Q(u)=0.023*r0^(-1/4)*u^(-14/4)
E(u1)= integral from u0 to u2 [Q(u)^(0.3)]du
where u is a range of numbers
u1 is between u0 and u2
Torsten
Torsten on 5 Jun 2024
E(u1)= integral from u0 to u2 [Q(u)^(0.3)]du
You define E as a function of u1, but u1 does not appear on the right-hand side.

Sign in to comment.

Answers (1)

Alan Stevens
Alan Stevens on 5 Jun 2024
Are you looking for something like this?
r0 =0.1;
u =[1:7]';
Q =zeros(length(u),1);
E =zeros(length(Q),1);
Q = @(x)0.023*(r0^(-1/4))*(x.^(-14/4));
f = @(x) Q(x).^0.3;
for i =1:length(u)
u0 = 1; u2 = u(i);
E(i,1) =integral(f,u0,u2);
end
disp(E)
0 0.2611 0.4097 0.5133 0.5927 0.6569 0.7107

Categories

Find more on Mathematics in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!