Linear indices from colon operator

2 views (last 30 days)
Radek
Radek on 14 Nov 2024
Edited: Stephen23 on 15 Nov 2024
Any array (let's consider only 2D here) can be indexed using colon operator such
array(p1:p2,p3:p4)
How can one generate list of linear indices (for that particular array) from parameters [p1, p2, p3, p4]?

Accepted Answer

Matt J
Matt J on 14 Nov 2024
[I,J]=ndgrid(p1:p2,p3:p4);
linear=sub2ind(size(array) , I,J);

More Answers (2)

Steven Lord
Steven Lord on 14 Nov 2024
See sub2ind.
  2 Comments
Stephen23
Stephen23 on 14 Nov 2024
Edited: Stephen23 on 15 Nov 2024
Note that in general p1:p2 and p3:p4 when used a indices like that will refer to a rectangular block of that array. So in order to get the linear indices of the entire block you will need to provide SUB2IND with subscript indices for the entire block. One way to achieve this is using NDGRID:
array = randi(9,9,9);
p1 = 3;
p2 = 5;
p3 = 2;
p4 = 5;
[X,Y] = ndgrid(p1:p2,p3:p4);
Z = sub2ind(size(array),X,Y);
array(Z)
ans = 3×4
4 7 2 6 9 9 6 7 1 2 4 8
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
array(p1:p2,p3:p4)
ans = 3×4
4 7 2 6 9 9 6 7 1 2 4 8
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
Walter Roberson
Walter Roberson on 14 Nov 2024
sub2ind() processes the indexes in parallel. All of the indices must be the same size (or else scalars)
sub2ind([4 5],1:2,1:3)
Error using sub2ind (line 61)
Subscript arguments must be scalars or arrays of the same size.

Sign in to comment.


Catalytic
Catalytic on 14 Nov 2024
Edited: Catalytic on 14 Nov 2024
K=createArray(size(array),Fill=sparse(0));
K(p1:p2,p3:p4)=1;
out=find(K); %linear indices
  1 Comment
Matt J
Matt J on 14 Nov 2024
I would probably do instead,
K=createArray(size(array),Fill=sparse(false));
or maybe just use,
K=false(size(array))
depending on the expected size of the output.

Sign in to comment.

Tags

Products


Release

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!