Clear Filters
Clear Filters

Write a function called one_per_n that returns the smallest positive integer n for which the sum 1 + 1/2 + 1/3 + … + 1/n , is greater than or equal to x where x is the input argument. Limit the maximum number n of terms in the sum to 10,000 .

3 views (last 30 days)
function out=one_per_n(x)
if x>10000
out=-1;
%fprintf('-1\n');
else
total=0;
for n=1:x;
total=(total+(1/n));
end
if total>=x
out=total;
%fprintf('%d\n',total);
end
end
  1 Comment
Adam
Adam on 22 May 2015
What exactly is your question? Just posting some code isn't very useful even if you do also paste a homework question into the title.

Sign in to comment.

Accepted Answer

Walter Roberson
Walter Roberson on 22 May 2015
Example:
for K = 1 : 50 %maximum 50 times
t = f(K); %some calculation dependent on the counter
if t >= SomeLimit %did we reach the limit?
break; %Yes! Stop this loop!
end
end
%now that we got here you need to figure out if you matched what you wanted to match, or if you ran out of iterations
%left as an exercise for the reader
  4 Comments
Christos Vyzantios
Christos Vyzantios on 31 May 2015
Edited: Walter Roberson on 1 Jun 2015
The solution seems ok but the greater saw us the message:
Problem 5 (one_per_n):
Feedback: Your function performed correctly for argument(s) 1
Feedback: Your function performed correctly for argument(s) 2
Feedback: Your function performed correctly for argument(s) 3
Feedback: Your function performed correctly for argument(s) 4
Feedback: Your function performed correctly for argument(s) 8
Feedback: Your function performed correctly for argument(s) 9
Feedback: Your function performed correctly for argument(s) 9.7875
Feedback: Your function performed correctly for argument(s) 9.7876
Feedback: Your function made an error for argument(s) 9.7877
Your solution is _not_ correct.
Walter Roberson
Walter Roberson on 1 Jun 2015
The problem statement from the title does not define what should happen when 10000 terms is not enough to reach the desired total.

Sign in to comment.

More Answers (4)

Chen Li
Chen Li on 17 Mar 2017
Edited: Chen Li on 17 Mar 2017
function d = holiday(month,day)
if month == 1 && day == 1
d = true;
elseif month == 7 && day == 4
d = true;
elseif month == 12 && day == 25
d = true;
elseif month == 12 && day == 31
d = true;
else
d = false;
end
This is the code that is based on what you wrote. Now it works!

Jean Araujo
Jean Araujo on 1 Jun 2015
function out = one_per_n(x)
total=0;
n = 1;
while total < x
total = (total+1/n);
n = n+1;
end
if n-1 > 10000
out = -1;
else
out = (n-1);
end

Nava  Subedi
Nava Subedi on 28 Nov 2016
Edited: Walter Roberson on 28 Nov 2016
I tried to solve the question.
Write a function called holiday that takes two input arguments called month and day; both are scalar integers representing a month (1-12) and a day (1-31). The function returns a logical true if the specified date is a holiday; if not, it returns false. For the purposes of this exercise, the following dates are considered holidays: January 1st, July 4th, December 25th, and December 31st.
I wrote:
function d = holiday(month, day)
if (month >= 1 && month <=12) && (day >= 1 && day <= 31)
if month == 1 && day == 1
d = 1
fprintf('%d is true! It is a holoday. \n', d);
end
if month == 7 && day == 4
d = 1
fprintf('%d is true! It is a holoday. \n', d);
end
if month == 12 && day == 25
d = 1
fprintf('%d is true! It is a holoday. \n', d);
end
if month == 12 && day == 31
d = 1
fprintf('%d is true! It is a holoday. \n', d);
end
else
d = 0
fprintf('%d is false! It is not a holoday. \n', d);
return
end
end
But did not work. Where did I do mistake??
  1 Comment
Walter Roberson
Walter Roberson on 28 Nov 2016
The assignment does not request any printing.
The assignment requires logical true and logical false as outputs, not double precision 1 and double precision 0. Logical true is represented as true and logical false is represented as false

Sign in to comment.


Jorge Briceño
Jorge Briceño on 29 Jan 2018
Hello Nava,
Maybe you could also try to simplify your code. Here is my example:
function out = holiday (m, d)
if (m==1 && d==1) || (m==7 && d==4)|| (m==12 && d==25)...
|| (m==12 && d==31)
out=true;
else
out=false;
end
return;
end

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!