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How to extract cell array in matlab

Asked by Mr Smart on 21 Nov 2011
Hello.. Anyone does know? I need to extract from cell array (1x1 cell). For example > '22.11.2011 13:58:56.16' from this (1x1 cell).I want to extract time in second (:56) .How can I do. Thanks.

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4 Answers

Answer by Fangjun Jiang
on 21 Nov 2011
 Accepted Answer

c={'22.11.2011 13:58:56.16','22.11.2011 13:58:40.16'};
d=datevec(c);
floor(d(:,6))

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Thanks for help :)

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Answer by Sven
on 21 Nov 2011

If you have strings of dates, use datevec as follows:
[Y, M, D, H, MN, S] = datevec('22.11.2011 13:58:56.16');
You'll notice that S has the value "56.1600", so floor(S) gives you the seconds

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Thanks you, Sven

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Answer by Andrei Bobrov
on 21 Nov 2011

out = datevec({'22.11.2011 13:58:56.16'},'dd.mm.yyyy HH:MM:SS')
out = out(end)
OR
out = sprintf(':%d',out(end))

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Show 1 older comment
Mine will! None of the rest of you noticed that the ':' was a mandatory part of the output!
@Sven: Walter :)
Thanks to you also . :)

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Answer by Walter Roberson
on 21 Nov 2011

> datestr(datenum({'22.11.2011 13:58:56.16'},'dd.mm.yyyy HH:MM:SS.FFF'),':SS')
ans =
:56
>> char(cellfun(@(T) T(end-5:end-3), {'22.11.2011 13:58:56.16'},'Uniform',0))
ans =
:56

  2 Comments

Based upon the previous answers, the following should also work:
datestr(datevec({'22.11.2011 13:58:56.16'}),':SS')
Thanks you, Walter

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