how to stop simulation when enter in a infinite loop

hi

how i deal in a situation where by mistake infinite loop initiate or where i want to see step by step response of any program or loop. kindly help me

regards

[B.k Sumedha]

U can use debug option or else use breakpoints.

Answer 1

[Geoff Hayes]

Mudasir - sometimes, if I have written some code that makes use of a while loop, I will include a maximum iteration counter to prevent the code from getting stuck in that loop. For example, if the while loop looks something like

 while someCondition
     % do something
 end

then I would change this to

 MAX_ITERATIONS = 1000;
 iterCount      = 0;

 while someCondition && iterCount <= MAX_ITERATIONS
     % do something

     iterCount = iterCount + 1;
 end

 if iterCount > MAX_ITERATIONS
     fprintf('exited loop perhaps because max iteration count reached\n');
 end

[Mudasir Ahmed]

thanks sir :)

[Image Analyst]

Using a failsafe like Geoff suggested is an excellent idea . I always do it and in fact, consider it an essential idea. I suggest you permanently adopt this essential programming concept. With my code, which needs to be super robust and validated, about half of the lines of code are taken up with comments, fail-safes, input validations, error checking, error logging, bulletproofing/foolproofing/idiotproofing, try/catch, attempted repair of bad inputs (workarounds), etc.

[Mudasir Ahmed]

sir as i apply above logic , following error occurs

while fitness(:,1)>2 && iterCount <= MAX_ITERATIONS

"Operands to the and && operators must be convertible to logical scalar values.""

[Geoff Hayes]

Mudsair - fitness must have more than one row. Note that fitness(:,1) will return a column vector of ones and zeros and so it is this column that is causing a problem with the conditional operator. What does the condition

 fitness(:,1) > 2

mean to you? Are you checking to see if all elements in the first column are greater than 2? Or, is this condition considered true (by you) if at least one element in the first column is greater than 2?

If the former, then use all as

 all(fitness(:,1)>2)

to return a single logical value (0 or 1). If the latter, then use any to determine if at least one value in your column is non-zero (i.e. one) as

 any(fitness(:,1)>2)

Try the option that best suits your needs.

[Mudasir Ahmed]

perfect answer sir :)