Matlab 2015a: figure() error

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Ryusuke
Ryusuke on 23 Oct 2015
Commented: Walter Roberson on 29 Oct 2015
以下のコードでエラーが出ます。理由を教えてください。環境はR2015aです。
fnum=-1;
fnum(fnum<1)=1;
figure(fnum);
---------------------
エラー: figure
簡易引数ハンドルが無効です
  1 Comment
Image Analyst
Image Analyst on 23 Oct 2015
What's the error? Please paste all the red text. You will get more answers if you post this in English. Why are you doing that anyway? fnum<1 is just true, which evaluates to 1. So then you're doing fnum(1) = 1, followed by figure(1). So why not just do figure(1) in the first place?

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Answers (1)

Sudhanshu Bhatt
Sudhanshu Bhatt on 29 Oct 2015
Hi Ryusuke,
Can you please explain more about the workflow you are trying to achieve? What is the error message you are receiving?
One possible reason for the error could be that you are passing "fnum" to FIGURE. If you want the value inside "fnum" to be passed to the FIGURE you can do something like this:
figHandle = figure(fnum(1));
Hope this helps.
Thanks
Sudhanshu Bhatt
  1 Comment
Walter Roberson
Walter Roberson on 29 Oct 2015
fnum in the shown code is a scalar. There is no difference, in this situation, between coding figure(fnum) and figure(fnum(1))

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