introducing your system in muPAD, as you keyed it in the answer, returns
Warning: 8 equations in 4 variables.
simplifying it to:
- d-.5*k*m*n=0
- n-m-10/k=0
- k*(n^2-m^2)+d*log(m/n)-(m+n)=0
- 1+(m^3+n^3)+k*(n^4-m^4)+d*(m^2-n^2)=0
muPAD return null, kind of can't find answer.
However, if you approximate log(x) (natural or Neper log) by only 1st Taylor series ln(x)~x-1, bear in mind that evaluating ln(x0)~x-x0-1 , then
- d-.5*k*m*n=0
- n-m-10/k=0
- k*(n^2-m^2)+d*(m/n)-1-(m+n)=0
- 1+(m^3+n^3)+k*(n^4-m^4)+d*(m^2-n^2)=0
muPAD returns
Use attached muPAD result file if you want to carry on from here.
If you find this answer of any help solving your question please click on thumbs-up vote above link, thanks in advance
John
note: d*log(m/n) should be d*m/n-d, not d*m/n-1