how do i add output of Fx and Fxd?

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ANIKET KADAM
ANIKET KADAM on 25 Feb 2016
Commented: ANIKET KADAM on 25 Feb 2016
F(row,i)= Fx + Fxd
  1 Comment
ANIKET KADAM
ANIKET KADAM on 25 Feb 2016
clc; clear all;
%%input time=0.2; K=170e6; C=15e-6; x=20e-6; y=20e-6;
%%initialize z = 13; %%z=13 H = 0.005; %%0.005m ld = 0.04; %%0.04m wc = 131; %%w=131rad/s theta = 360/z; tempphi=0; tempsi=0; row = 1; j=1; %counter for increment in defect angle
for t=0:37e-6:time %%time increment si(j)=tempsi; %%initialize defect angle
for i=1:1:z %%ball increment
phi(i)=tempphi; %%ith ball angle
disp('phi = '); phi(i)
if (phi(i) == si(j)) %%condition for ball in defect region
thetat = (wc*t) + (2*3.14/z*(z-i))
Fxd(row,i)= K* (x* cos(phi(i)*(pi/180)) + y* sin(phi(i)*(pi/180)) - (C + H * sin(3.14/(ld*(thetat-phi(i)*(pi/180)))))).^(3/2) * cos(phi(i)*(pi/180));
disp('Fxd value');
disp(Fxd(row,i));
Fyd(row,i)= K* (x* cos(phi(i)*(pi/180)) + y* sin(phi(i)*(pi/180)) - (C + H * sin(3.14/(ld*(thetat-phi(i)*(pi/180)))))).^(3/2) * sin(phi(i)*(pi/180));
disp('Fyd value');
disp(Fyd(row,i));
disp('defect ball position');
else %%condition for ball in non-defect region
Fx(row,i)= K* (x* cos(phi(i)*(pi/180)) + y* sin(phi(i)*(pi/180)) - C).^(3/2) * cos(phi(i)*(pi/180));
disp('Fx value');
disp(Fx(row,i));
Fy(row,i)= K* (x* cos(phi(i)*(pi/180)) + y* sin(phi(i)*(pi/180)) - C).^(3/2) * sin(phi(i)*(pi/180));
disp('Fy value');
disp(Fy(row,i));
disp('other balls position');
end
tempphi = phi(i) + theta;
end
tempphi = 0;
tempsi = si(j) + 45;
if(tempsi >= 360)
tempsi = 0
end
j = j + 1;
row = row + 1;
end

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Answers (1)

Jos (10584)
Jos (10584) on 25 Feb 2016
What do these 5 variables in the statement " F(row,i)= Fx + Fxd" hold?
To be added like this, Fx and Fxd should have of the same size. The sum (Fx + Dxd) has that size as well. This should fit in the position in F indicated by row and i. So, F(row,i) should have that size as well. If F does not exist, you might want to omit the indices (row,i)
You can check all this by looking at these individual elements of the statement.
  1 Comment
ANIKET KADAM
ANIKET KADAM on 25 Feb 2016
thankyou for answer. there was an attached file along with question which displayed the variables meaning.

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