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# Hi, so I'm trying to plot this equation: y=-(sqrt(288-2*x.^4))/x with x=0:0.05:3.267 but y is giving me a single answer (-6.55) and when i do plot(x,y) the graph is empty! Can someone help me please!

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### Answers (3)

Ingrid
on 29 Feb 2016

you have forgotten to also use the ./ operator instead of the / operator. The code below should give what you try to achieve

x=0:0.05:3.267;

y=-(sqrt(288-2*x.^4))./x;

plot(x,y)

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Jos (10584)
on 29 Feb 2016

The plot is not empty. It contains 66 points all having the same y value (at y=-6.5514), which can be seen here:

plot(x,y,'bo')

Why is y a scalar? Because, as others told you already, there is a difference between element-wise (.* and ./) and matrix operators (* and /):

x = 1:4

x ./ x

x / x

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