FFT function code from YouTube not working

2 views (last 30 days)
Tom
Tom on 26 Jan 2012
The original question has been removed by the user.

Sign in to answer this question.

Accepted Answer

Dr. Seis
Dr. Seis on 26 Jan 2012
Did you mean:
X = X(1:cutOff);

More Answers (0)

Categories

Find more on Fourier Analysis and Filtering in Help Center and File Exchange

Tags

Products

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!