How to speed up conv2 and finite difference method?
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Hi, I would like to know if there is an opportunity to speed up a code listed below. Convolution method (CM) is a bit slower (40s) than iteration method(IM) (25s). Can this code (either or both methods) be improved further for speed? Note that Wnew and Znew are not exactly the same. (edges of matrix Znew are nonzero)
% iteration method
N=200;
Wold=zeros(N,N);
Wnew=zeros(N,N);
W=zeros(N,N);
Z=zeros(N,N);
Znew=zeros(N,N);
Zold=zeros(N,N);
W(10,10)=10;
Z(10,10)=10;
j = 2:N-1;
i = 2:N-1;
tic;
for time=0:0.1:100
Wnew(j,i)=a*(W(j+1,i)-4*W(j,i)+W(j-1,i)+W(j,i+1)+W(j,i-1))+2*W(j,i)-Wold(j,i);
% algorithm for display is here the same as for CM
Wold=W;
end
toc
% convolution method
D=[0 1 0; 1 -4 1; 0 1 0];
tic;
for time=0:1:100
Znew=2*Z-Zold+a*conv2(Z,D,'same');
% algorithm for display is here the same as for IM
Zold=Z;
end;
toc
5 Comments
CS Researcher
on 5 May 2016
Why do you have the two for loops here? The iterator is on time but you do not use that anywhere.
mathango
on 5 May 2016
Adam
on 5 May 2016
Convolution can be speeded up by using an fft-based implementation in some cases, but it depends on the quantity of data. There is a crossover point beyond which the time taken to do the fft and ifft is outweighed by the faster operation of convolution in the frequency domain, but to know if it is worth it you would need to implement it and test the speed.
CS Researcher
on 6 May 2016
I will again ask the same thing. Why do you have the for loops there? You are running the same commands in a loop without any change.
Adam
on 6 May 2016
Also you should use
doc profile
rather than tic toc if you seriously wish to optimise code.
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