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How do you have a logical operator of true and false as your type but 0 and 1 as your value?

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Hi. I am having trouble with this homework question: Write a function called eligible that helps the admission officer of the Graduate School of Vanderbilt University decide whether the applicant is eligible for admission based on GRE scores. The function takes two positive scalars called v and q as input. They represent the percentiles of the verbal and quantitative portions of the GRE respectively. You do not need to check the input. The applicant is eligible if the average percentile is at least 92% and both of the individual percentiles are over 88%. The function returns the logical true or false. What I have attempted is below:
function [true, false] = eligible(v, q)
if mean(v, q)>= 92 && v>88 && q>88
fprintf('true\n');
elseif mean(v, q)<92
fprintf('false\n');
elseif v<=88
fprintf('false\n');
elseif q<=88
fprintf('false\n');
I think my problem is that I need the false to appear as the type but 0 to appear as my value and true to appear as the type but 1 to appear as my value.

Accepted Answer

Image Analyst
Image Analyst on 8 Aug 2016
You used mean() incorrectly. Look at this:
>> mean(10,30) % WRONG!
ans =
10
>> mean([10,30]) % Right way uses brackets.
ans =
20
So instead of
if mean(v, q)>= 92 && v>88 && q>88
fprintf('true\n');
elseif mean(v, q)<92
fprintf('false\n');
elseif v<=88
fprintf('false\n');
elseif q<=88
fprintf('false\n');
use
if mean([v, q]) >= 92 && v > 88 && q > 88
fprintf('true\n');
isEligible = true;
else
fprintf('false\n');
isEligible = false;
end
  3 Comments
the cyclist
the cyclist on 18 Feb 2018
Or, if you are playing Cody ...
function ans = eligible(v,q)
((v+q)>=184)&&(v>88&&q>88);
[This is not a serious comment. Please do not take it as such!]

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More Answers (7)

the cyclist
the cyclist on 8 Aug 2016
You are on the right track. Here is a hint ...
Instead of outputting two variables named true and false, I think you'd want to just output one variable -- maybe call it isEligible -- that takes on the values true/false.
It looks like you know how to calculate the value of isEligible, because you have used it to determine what to display to the screen.

Jorge Briceño
Jorge Briceño on 28 Jan 2018
Hi Alexandra,
Maybe another alternative would be:
function [isEligible]=eligible( v,q )
Your_Output_Name= v>88 && q>88 && ((q+v)/2)>=92
end
Cheers, Jorge

ledinh lam
ledinh lam on 25 Nov 2016
Edited: DGM on 3 Mar 2023
I think it will be :
function el=eligible(v,q)
if mean([v,q]) >= 92 && v>88 && q >88
el=true;
else
el=false;
end
end

Duddela Sai Prashanth
Duddela Sai Prashanth on 23 Sep 2018
function [out] = eligible(v, q)
if v > 88 && q > 88 && (v+q)/2 >= 92
out = true;
else
out = false;
end

Yamen Al-Jajan
Yamen Al-Jajan on 23 Nov 2019
function admit=eligible(v,q)
if v>=88 & q>=88
ave=(v+q)/2;
if ave>=92
admit=true;
else
admit=false;
end
else
admit=false;
end

Rahul Krishna
Rahul Krishna on 31 May 2021
function admit = eligible(v,q)
if (q +v)/2 >=92 && (v>88 && q>88)
admit = true
fprintf(' the candidate is eligible \n')
else
admit = false
fprintf(' the candidate is not eligible \n')
end

MALK adil
MALK adil on 29 Dec 2021
function out = eligible(v,q)
out = (v+q)./2 >= 92 && v > 88 && q > 88;
if out==1
out= true;
else out= false;
end
  1 Comment
Image Analyst
Image Analyst on 29 Dec 2021
Edited: Image Analyst on 29 Dec 2021
@MALK adil your if block is totally unnecessary.
out is already a boolean (true or false) by how you define it. You do not need to check if it's a 1 (double) and then assign it to true (which it already is). I believe that when you compare a logical to a double (like bln == 7) it converts the logical to a double (false converts to 0, and true converts to 1) and then it compares that double to the number (7) and returns a double.
out = true
out = logical
1
result = out == 7 % Convert out to double then compare the two doubles and return a logical
result = logical
0
And if it's not 1 (the only other choice is false) there is no need to set it to false. It's already false!
So you could simply have done
function out = eligible(v,q)
out = (v+q)./2 >= 92 && v > 88 && q > 88;

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