How I plot parametric ellipse ,, tangenten and perpendicular.?

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1)Give ellipse (x-1)^2+y^2/4=1 after some calculation I got x= cost +1 y= 2sint (parametric equations)
2)Find a unit tangent vector, parametric equations of the tangent and perpendicular in point (1, 2). after some calculation I got unit tangent vector (1,2) tangent (0,-2) perpendicular (1,0)
I got the matlab code from lecture but I try to changes the equations to mine but is not work.
close all % Approximation of an ellipse (parametrized!) (x/2)^2+(y/3)^2=1. for i=5:10 % define the parameter t t = 0:2*pi/i:2*pi; % plot parametric curve plot(sqrt(cos(t)+1)), sqrt(2)*sin(t); axis equal; xlim([-2,2]); ylim([-2,2]); % set a grid on the plot grid on; title(sprintf('Approximation of the ellipse (x/2)^2+(y/3)^2=1 with i = %i', i)); pause(1); end
If somebody have better and easier solution please give me advice..
thank you!
  1 Comment
Ramesh Bala
Ramesh Bala on 26 Jul 2018
%parametric form
t = linspace(0, 2*pi, 200);
xt = r1 * cos(t) + xc; yt = r2 * sin(t) + yc;
% aply rotation by angle theta
cot = cos(theta); sit = sin(theta);
x = xt * cot - yt * sit;
y = xt * sit - yt * cot;
plot(x, y, '-');

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Answers (1)

Ajey Pandey
Ajey Pandey on 26 Jul 2018
To piggyback off Kaleesh's comment, the documentation for plot offers a tutorial for plotting parametric equations.
Look for the "Plot Circle" example.
  1 Comment
Ramesh Bala
Ramesh Bala on 27 Jul 2018
yeah thanks in circle case it's same radii and axis equal.In ellipse r varies.So,if one knows r1 ,using formulation can get r2.
So any idea to get r1 from foci?

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