Making an array Fails for mysterious reason (small stepsize)
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In short:
fs = 50000;
x1 = (0:1/fs:1);
find(x1==0.5)
This works fine. The value of 0.5 is found in the array.
fs = 50000;
x2 = ( 0:1/fs:(1-1/fs) );
find(x2==0.5)
Does not work. The value of 0.5 is not there anymore and the find-function returns an empty matrix. I would have expected that x2 would be the equivalent of x1(1:end-1) but that does not seem to be the case. For smaller values fs (e.g. 5000) everything is fine. Can someone tell me what is going on exactly?
Thanks
Accepted Answer
More Answers (1)
KSSV
on 21 Sep 2016
1 vote
It is not advised to compare floating point numbers using ==. You have to fix a small number (tolerance) say, eps = 10^-5 and check for is the absolute difference less then that. If so then the floating point numbers are close enough. '
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