Imagine I have a number that is all the numbers in the universe stuck to eachother, from 1 to infinity. (123456789​1011121314​1516171819​20212223..​.). How can I write a code that says: If I have a number n, what is the nth digit of this gigantic number?

I couldn't come up with a solution yet

Answer 1

[michael]

just use

mod, floor

functions

a=17
b=a
mod(b,10)      <=== you will get 7
repeat till the n-th digit    (n=2)
  b=floor(b/10)
  mod(b,10)   <=== you will get 1