# Find the x value from a specific iteration of fmincon

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boureghda mohammed on 5 Dec 2016
Edited: Massimo Zanetti on 13 Dec 2016
How can I extract the the value of x at the iteration 5 when f(x)= 0.300877 after the optimization procedure.
Max Line search Directional First-order
Iter F-count f(x) constraint steplength derivative optimality Procedure
0 3 1 -1
1 9 0.953127 -0.9375 0.125 -2 12.5
2 16 0.808446 -0.8601 0.0625 -2.41 12.4
3 21 0.462347 -0.836 0.25 -12.5 5.15
4 24 0.340677 -0.7969 1 -4.07 0.811
5 27 0.300877 -0.7193 1 -0.912 3.72
6 30 0.261949 -0.6783 1 -1.07 3.02
7 33 0.164971 -0.4972 1 -0.908 2.29
8 36 0.110766 -0.3427 1 -0.833 2

Massimo Zanetti on 5 Dec 2016
Edited: Massimo Zanetti on 13 Dec 2016
From the help page about Output Functions Output Functions you can extract this way to save iterates of the solver. Assume you want to minimize the function f(x1,x2) = 4*x1^2 + 2*x2^2, then:
1. Define your problem by nesting functions into one main function:
function [x fval history] = myproblem(x0)
history = [];
options = optimset('OutputFcn', @myoutput);
[x fval] = fminsearch(@objfun, x0,options);
function stop = myoutput(x,optimvalues,state);
stop = false;
if isequal(state,'iter')
history = [history; x];
end
end
function z = objfun(x)
z = 4*x(1)^2+2*x(2)^2;
end
end
1. Trigger the solver (with one starting value x0) and retrieve all iterates the solver has computed in the matrix history
x0 = [1,2];
[x,val,history] = myproblem(x0);
Inspect matrix history, each row is the k-th iterate. The same procedure works for fmincon.