How to replace zeros in one matrix with another matrix

Hello, how to replace zeros in one matrix with another matrix using if statement? Dimensions are the same; first matrix has 10 zeros and second matrix has 10 numbers. Thanks for answers J

[Geoff Hayes]

J - how does the condition work? Are you iterating over each element and if the element is zero then replace with the equivalent element in the other matrix?

[Geoff Hayes]

J's answer moved here

Matrix B=[1 0 0 0 0;2 3 0 0 0;4 5 6 0 0;7 8 9 10 0;11 12 13 14 15] You can see that "triu" of matrix B is made of zeros. I need to replace zeros in matrix B using IF statement with matrix A=[1 2 3 4 5;6 7 8 9 10]. Orientation is set and number of zeros is matching matrix A.

[Guillaume]

The first option in my answer matches this scenario. if is not needed.

Answer 1

[Andrei Bobrov]

A = [1:3, 0,0 7,12,0]';% your first array
B = randi(20,8,1);     % your second array

t = A == 0;
A(t) = B(t);

Answer 2

[Guillaume]

An example would clarify what you want. Possibly:

To replace all zero values in A by consecutive values in B, B must have as many elements as there are zeros in A:

assert(numel(B) == numel(A == 0));  %B must have as many elements as there are zeros in A
A(A == 0) = B                       %replace zeros values in A by values in B

or to replace zeros values in A by values in B in the same position, B must be the same size as A:

assert(isequal(size(B), size(A)));
A(A == 0) = B(A == 0)

An if is most likely not needed.

Answer 3

[arwa]

x = [0 0 0 0 0 0 0 0 0 0]; z = [1 2 3 4 5 6 7 8 9 10]; for i=1:1:10 x(1:i)=z(1:i); end

then you can get x = [1 2 3 4 5 6 7 8 9 10] like z instead of zeros..

Do you mean this??