How to find the second closest number?

I have a matrix looks like this:

A = [1990;1993;1998;2001;2004 ]

And I would like to find the closest value to f=1999 (in this case the first closest value is certainly 1998), but how can I find the second closest value (2001) after I found the first value.

Thanks before

[David Goodmanson]

Hi Yuli, if you take abs(A-your_number) and sort it, you will get the entire list of distances. The sort command also has a second output that will show you the location of each one in the unsorted array.

Answer 1

[KSSV]

clc; clear all ;
A = [1990;1993;1998;2001;2004 ] ;
f = 1999 ;
[val,idx] = sort(abs(f-A)) ;
A(idx)