Calculating the length of a curve

Hi everyone,

can anybody tell me how to calculate the length of a curve being defined in polar coordinate system using following equation? z=21-2*cos(1.5*(tet-7*pi/6))

for tet=[pi/2:0.001:pi/2+2*pi/3].

I put the code here too and many thanks in advance.

tet=[pi/2:0.001:pi/2+2*pi/3];
z=21-2*cos(1.5*(tet-pi/2-pi/3));
polar(tet,z)

[Jyotish Robin]

To find the length of a curve y=f(x), we can make use of the formula:

 L =integral(sqrt(1+(dy/dx)^2));

Now you can make use of the functions "diff" and "int" in MATLAB to perform differentiation and integration operations.

As an alternative to "int" function, you can try using "quad" function also.

The following link is worth looking: https://www.mathworks.com/matlabcentral/newsreader/view_thread/20241

Hope this helps !