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a(a(a>3)<10) = OK ; a(a>3 && a<10) = wrong!, the correct way?

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a=[1 2 3 4 11 33]; I want to get the number in a from 4-9; a(a(a>3)<10) is right; a(a>3 && a<10) is wrong -- is there other correct way to make this ?

Accepted Answer

Alexandra Harkai
Alexandra Harkai on 27 Feb 2017
If you want to get only values between 3 and 10 (excluding the endpoints), the correct way would be:
a(a>3 & a<10)
(Not exactly sure what you meant by 'OK' but a(a(a>3)<10) definitely gives some unexpected results.)
John D'Errico
John D'Errico on 27 Feb 2017
Note that Alexandra used a single & operator there. This is correct when you are anding together boolean vectors. Use && only in things like a test in an if statement.
Leotsing on 27 Feb 2017
Edited: Leotsing on 27 Feb 2017
thank you and other people answered! that"OK" means it works well to the result,but I think it is not good,so I asked.BTW, I also thought about FIND function,but never come to "&" .thank you again!

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