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Hello i want to know if exist a function that generate numbers in a range that i want to fix. for example i need to generate 22 numbers in this range: 0.5000 and 0.600
can you help me? thank you

1 Comment

Aldin
Aldin on 20 Mar 2012
Here:
0.5:0.1/20:0.6

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Answers (2)

Aldin
Aldin on 20 Mar 2012

0 votes

Here:
0.5:0.1/20:0.6
Beacuase: (0.6 - 0.5)/20

5 Comments

Oleg Komarov
Oleg Komarov on 20 Mar 2012
Actually it's:
a = 0.5:0.1/21:0.6;
Alternatively a high level function (which uses the engine showed by Aldin)
b = linspace(.5,.6,22);
Geoff
Geoff on 20 Mar 2012
Using linspace to generate a series is preferable here because it has more transparent semantics. _ie_ "I want 22 values between A and B". It's also easier to change the range without introducing errors. What if you decided you needed to go between 0.5 and 0.7? How will you make sure you don't make a mistake with the colon operator?
Aldin
Aldin on 20 Mar 2012
Hi Oleg, when yout write 0.1/21 the length of the vector is 23 not 22
Oleg Komarov
Oleg Komarov on 20 Mar 2012
In my case is 22.
Geoff
Geoff on 20 Mar 2012
Oleg is correct: length( 0.5:0.1/20:0.6 ) is 21. You really should use linspace if you want a linear sequence with a specified number of elements. That's what it's there for.

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Geoff
Geoff on 20 Mar 2012

0 votes

You haven't really specified if you want a sequence or just a set of numbers. Picking up on your term 'generate', perhaps you meant this:
randarr = @(lo, hi, n) lo + (hi-lo) * rand(1,n);
data = randarr(0.5, 0.6, 22);
That creates a bunch of random numbers in your specified range. Note I've wrapped it in an anonymous function to give the same syntax as linspace.

1 Comment

Geoff
Geoff on 20 Mar 2012
Oops, just realised I specified that anonymous function incorrectly. Fixed.

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on 20 Mar 2012

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