How can we find the non common strings from multiple columns
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Dear all,
I want to compare the following three columns of strings (of different length) and find the entries that are NOT common across them. Just to mention that my real vectors (listA,listB,listC, etc) are of large size.
    listA={'India'
    'Iran'
    'Ireland'
    'Israel'
    'Jordan'
    'Kuwait'
    'Lebanon'
    'Lesotho'
    'Libya'
    'Luxembourg'
    'Malawi'
    'Maldives'
    'Morocco'
    'Nepal'
    'Netherlands'
    'Norway'
    'Oman'
    'Paraguay'
    'Peru'
    'Philippines'
    }; listB={    'Denmark'
    'El Salvador'
    'Gabon'
    'Gambia'
    'Lebanon'
    'Lesotho'
    'Libya'
    'Luxembourg'
    'Malawi'
    'Maldives'
    'Morocco'
    'Nepal'
    'Netherlands'
    'Norway'
    'Oman'
    'Paraguay'
    'Peru'
    'Philippines'
    'Qatar'
    'Rwanda'
    'Saudi Arabia'
    'Senegal'
    'Singapore'
    'Sudan'}; listC= {'Kuwait'
    'Lebanon'
    'Lesotho'
    'Nepal'
    'Netherlands'
    'Oman'
    'Sweden'
    'Syria'
    'Tanzania'
    'Turkey'
    'Uruguay'};
    Accepted Answer
  Stephen23
      
      
 on 13 Mar 2017
        
      Edited: Stephen23
      
      
 on 13 Mar 2017
  
      First lets find the strings that are common to all cell arrays:
listA={'India','Iran','Ireland','Israel','Jordan','Kuwait','Lebanon','Lesotho','Libya','Luxembourg','Malawi','Maldives','Morocco','Nepal','Netherlands','Norway','Oman','Paraguay','Peru','Philippines',};
listB={'Denmark','El Salvador','Gabon','Gambia','Lebanon','Lesotho','Libya','Luxembourg','Malawi','Maldives','Morocco','Nepal','Netherlands','Norway','Oman','Paraguay','Peru','Philippines','Qatar','Rwanda','Saudi Arabia','Senegal','Singapore','Sudan'};
listC={'Kuwait','Lebanon','Lesotho','Nepal','Netherlands','Oman','Sweden','Syria','Tanzania','Turkey','Uruguay'};
%
lists = {listA,listB,listC}; % storing data together makes working with them much simpler.
%
exc = lists{1};
for k = 2:numel(lists)
    exc = intersect(exc,lists{k});
end
giving the strings found in all cell arrays as:
 exc =
    'Lebanon'
    'Lesotho'
    'Nepal'
    'Netherlands'
    'Oman'
Now we can easily get the input cell arrays with the strings from exc removed:
out = cell(size(lists));
for k = 1:numel(lists)
    out{k} = setdiff(lists{k},exc);
end
giving:
>> out{:}
ans = 
    'India' 'Iran' 'Ireland' 'Israel' 'Jordan' 'Kuwait' 'Libya' 'Luxembourg' 'Malawi' 'Maldives' 'Morocco' 'Norway' 'Paraguay' 'Peru' 'Philippines'
ans =
    'Denmark' 'El Salvador' 'Gabon' 'Gambia' 'Libya' 'Luxembourg' 'Malawi' 'Maldives' 'Morocco' 'Norway' 'Paraguay' 'Peru' 'Philippines' 'Qatar' 'Rwanda' 'Saudi Arabia' 'Senegal' 'Singapore' 'Sudan'
ans =
    'Kuwait' 'Sweden' 'Syria' 'Tanzania' 'Turkey' 'Uruguay'
And if you want a list of all strings together, excluding those in exc:
uni = {};
for k = 1:numel(lists)
    uni = union(uni,lists{k});
end
uni = setdiff(uni,exc)
gives:
uni =
    'Denmark' 'El Salvador' 'Gabon' 'Gambia' 'India' 'Iran' 'Ireland' 'Israel' 'Jordan' 'Kuwait' 'Libya' 'Luxembourg' 'Malawi' 'Maldives' 'Morocco' 'Norway' 'Paraguay' 'Peru' 'Philippines' 'Qatar' 'Rwanda' 'Saudi Arabia' 'Senegal' 'Singapore' 'Sudan' 'Sweden' 'Syria' 'Tanzania' 'Turkey' 'Uruguay'
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