Counting consecutive values in a matrix

Hello, I'm having trouble keeping tally of my 1's and 0's within a matrix. I simulated a coin flip lets say a 100 times. It'll list values within a (100,1) matrix. I want to create some loops that will count how many one's in a row and how many zeros in a row and it'll alternate. For example lets say A = [1,0,1,1,1,0,0,0,0,1,0,0,1....] so the result would yield B = [1,1,3,4,1,2,1...] Thanks!

Answer 1

[Guillaume]

No loop needed:

diff([0 find(diff(A)) numel(A)])

[Gabriela Garcia]

Do you know how could one do this for columns?

[Bruno Luong]

if isrow(A)
    diff([0, find(diff(A)), numel(A)])
else
    diff([0; find(diff(A)); numel(A)])
end