Info

This question is closed. Reopen it to edit or answer.

how to simulate a function

1 view (last 30 days)
Fatma Abdullah
Fatma Abdullah on 31 May 2017
Closed: Stephen23 on 31 May 2017
i'm trying to simulate this function "pd" against "lnd" by accept reject monte carlo method but it takes forever and nothing comes out
M=8;
N=32;
K=14;
c=2;
s=1;
T=18.623390280430364437245197384232;
lnd=0:5:30;
pd1=(2*K*nchoosek(N/2,K)*((gamma(K+i)*gamma(N-K+i+1+T./(1+lnd)))./(gamma(N+1+T./(1+lnd)))-...
(symsum(nchoosek(N/2,i)*(gamma(K+i)*gamma(N-K-i+1+T./(1+lnd)))./(gamma(N+1+T./(1+lnd))), i, K, (N/2)))));
%lnd=0:5:30;
pd=(symsum(nchoosek(M,i)*(pd1).^(i).* (1-(pd1)).^(M-i), i, s, M));
O=10^7;
Mx=1.2*max(pd);
lndi=10*rand(1,O);
pj=10*rand(1,O);
pd1i=2*K*nchoosek(N/2,K)*((gamma(K+i)*gamma(N-K+i+1+T./(1+lndi)))./(gamma(N+1+T./(1+lndi)))-...
(symsum(nchoosek(N/2,i)*(gamma(K+i)*gamma(N-K-i+1+T./(1+lndi)))./(gamma(N+1+T./(1+lndi))), i, K, (N/2))));
f_lndi=(symsum(nchoosek(M,i)*(pd1i).^(i)* (1-(pd1i)).^(M-i), i, s, M));
comp=pj*Mx;
result=f_lndi>=comp;
index=find(result);
lnd_new=lndi(1,index);
[pd1,lnd1]=hist(lnd_new,100);
dlnd=(lnd1(2)-lnd1(1));
h=(pd1/length(lnd_new))/dlnd;
plot(lnd1,h,'b.');

Answers (1)

Walter Roberson
Walter Roberson on 31 May 2017
As I told you in https://www.mathworks.com/matlabcentral/answers/342612-why-does-it-take-forever-to-solve-a-function, do not use symsum() for adding definite symbolic terms.

This question is closed.

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!