How we can combine two different series and add them

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Suppose we have two different sets of arithmetic series ranging from 1 to n. how to combine or add them together so that the elements are not repeated.
  4 Comments
KSSV
KSSV on 4 Aug 2017
That's what...it would be a number...adding numbers is not a deal...
Cong Ba
Cong Ba on 4 Aug 2017
Could you provide an input&output pair so people understand what you expect?

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Answers (2)

John BG
John BG on 4 Aug 2017
1.
generating 2 sequences
p=randi([-10 10],1,12)
q=randi([-10 10],1,12)
p =
7 9 -8 9 3 -8 -5 1 10 10 -7 10
q =
10 0 6 -8 -2 9 6 10 3 -10 7 9
2.
calculating X
either by applying the first expression directly
p([1:2:end]).*q([2:2:end])
=
0 64 27 -50 -100 -63
X=sum(p([1:2:end]).*q([2:2:end]))
=
-122
or adding q(0)=0 just in case
q=[0 q]
X=sum(p([1:2:end]).*q([2:2:end]))
=
-122
same result
3.
calculating Y
Y=sum(p([2:2:end]).*q([1:2:end]))
=
266
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thanks in advance
John BG

Jan
Jan on 5 Aug 2017
Edited: Jan on 5 Aug 2017
If you provide the input data and show what you have tried so far, posting an answer would require less guessing. I guess that p and q are vectors with n = length(p) / 2. Then what about:
X = 0;
for k = 2:2:n+1
X = X + p(k) * q(k-1);
end
Y = 0;
for c = 2:n
Y = p(2 * c) * q(2 * c - 1);
end
R = X + Y;
Note that I've shifted the indices by one, because they start at 1 in Matlab, not at 0, such that q(k-1) would fail for k=1. If this replies the wanted result, try:
R = sum(p(2:2:n+1) .* q(1:2:n)) + sum(p(2 * (2:n)) .* q(2 * (2:n) - 1))
or slightly faster:
R = sum(p(2:2:n+1) .* q(1:2:n)) + sum(p(4:2:2*n) .* q(4:2:2*n-1))

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