Reading large data set from text file & separating to individual column

1 view (last 30 days)
Hello, I have a text file in foll. format:
1950/05/21 04:00:00 1.7100 1 1
1950/05/21 05:00:00 1.5500 1 1
1950/05/21 06:00:00 1.4000 1 1
1950/05/21 07:00:00 1.2200 1 1
I need to separate it to individual column elements. The desired output is as below:
1950 05 21 04 1.71 1 1
1950 05 21 05 1.55 1 1
1950 05 21 06 1.40 1 1
1950 05 21 07 1.22 1 1
Please suggest codes for this. Thanks

Accepted Answer

José-Luis
José-Luis on 11 Aug 2017
Edited: José-Luis on 11 Aug 2017
Read in your data and then:
dummy = '1950/05/21 04:00:00 1.7100 1 1';
result = regexprep(dummy,'[\s/:]+',' ')
If you just want to edit a text file like that, there probably are better tools than Matlab for that. grep, for instance.

More Answers (2)

KSSV
KSSV on 11 Aug 2017
T = readtable('data.txt') ;
T = table2cell(T) ;
dt = strcat(T(:,1), '/',T(:,2)) ;
T = [dt T(:,3:end)] ;
iwant = [datevec(T(:,1)) cell2mat(T(:,2)) cell2mat(T(:,3)) cell2mat(T(:,4))]

Andrei Bobrov
Andrei Bobrov on 11 Aug 2017
T = readtable('doc.txt')
[a,b,c,d] = datevec(datetime(strcat(T{:,1},{' '},T{:,2}),'I','yyyy/MM/dd HH:mm:ss'));
out = [a,b,c,d,T{:,3:5}]

Categories

Find more on Data Import and Export in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!