Replacing Values of a Larger Matrix with that of a Smaller Matrix

I have a matrix A that looks like:

1 1 1 1 1 1 1 1 1 1                                                           
1 1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1

and a matrix B that looks like:

0 0
0 0
0 0
0 0
0 0
0 0

How can I create a new matrix C that looks like:

0 0 1 1 0 0 1 1 0 0                                                           
0 0 1 1 0 0 1 1 0 0
0 0 1 1 0 0 1 1 0 0
0 0 1 1 0 0 1 1 0 0
0 0 1 1 0 0 1 1 0 0
0 0 1 1 0 0 1 1 0 0

by inserting B into A and without using loops. Also if this is not possible, is there a way to create matrix C from matrix A?

Answer 1

[Cedric]

 b = mod( floor( (0:size( A, 2 )-1)/2 ), 2 ) ;
 C = bsxfun( @times, A, b ) ;

Note that the way I define b=00110011.. is ... shows that I am tired!

[Richard Zareck]

Thank you!!

[Cedric]

My pleasure. I answered thinking that you wanted to "mask" columns of A, hence the multiplication by 0 and 1 of given columns. Let me know if the purpose was different.

Answer 2

[Jose Marques]

imgSiz = [x1,y1];
blkSiz = [x1,size_column];
numRep = imgSiz./blkSiz;
basMat = toeplitz(mod(0:numRep(1)-1,2),mod(0:numRep(2)-1,2));
mask(:,:) = repelem(basMat,x1,size_column);