How to find are under the curve for a random signal.

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I have this random signal, is it possible that I find the are under the curve ?
Thanks for any help provided.

Accepted Answer

Kaushik Lakshminarasimhan
If samples are all uniformly spaced in time, you just need to take the sum of all elements.
area_under_signal = sum(my_signal)
Note that this number will be proportional, but not exactly equal to the actual area. If you need the exact number, you need to multiply by the temporal resolution of your signal, dt.
area_under_signal = sum(my_signal)*dt
  2 Comments
Karl Rueth
Karl Rueth on 9 Nov 2017
Mr. Kaushik,
Thanks for your reply; when applying the "sum" method, it is giving me a vector which makes sense. However when trying to multiply it whit "dt" it is giving me an error: "Undefined function or variable 'dt'" , can you pleae guide me.
Thanks
Kaushik Lakshminarasimhan
Kaushik Lakshminarasimhan on 10 Nov 2017
Of course, you need to define it before using. You should know the temporal resolution of your signal (how frequently you sample the signal). For example, if you have a vector of time points t at which you store your EMG signal x, then you can calculate dt and then use it to compute area:
dt = median(diff(t)); %median is just to take care of rounding errors
auc = sum(x)*dt;

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More Answers (1)

M
M on 8 Nov 2017
Try with this function
trapz
which does trapezoidal numerical integration.
  1 Comment
Star Strider
Star Strider on 10 Nov 2017
The trapz (or cumtrapz) functions are the appropriate functions for this problem.

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