how to sort in increasing order using loop?

for i=1:6
A(i)=input('')
end
for i=1:6
for j=1:5
if A(j)>=A(j+1)
B=A(j);
A(j)=A(j+1);
A(j+1)=B;
end
end
end

6 Comments

Hello baiti, what don't you like about this? It's a bubble sort in increasing order and it works.
then, i think my matlab is the problem. i really dont have any idea why it wont work on my matlab. any suggestion?
It's cleaner to put A = zeros(1,6) at the beginning, so that if you run the script more than once you get a fresh start for A. I put disp(A) at the end as well, so that you can see the results of your efforts.
To format your code read this
Why don't you just use the built-in sort() function?
@baiti: It seems like you have a problem running this code. Then it would be useful, if you mention what the problem is. "it wont work on my matlab" does not allow to reconsider, why you are not satisfied.
Do you want better algorithm than this?

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Answers (1)

for i=1:6
A(i)=input('')
end
for i=1:6
for j=1:5
if A(j)>=A(j+1)
B=A(j);
A(j)=A(j+1);
A(j+1)=B;
end
end
end

Categories

Find more on Loops and Conditional Statements in Help Center and File Exchange

Asked:

on 16 Dec 2017

Answered:

on 18 Sep 2020

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