how to sort in increasing order using loop?
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for i=1:6
A(i)=input('')
end
for i=1:6
for j=1:5
if A(j)>=A(j+1)
B=A(j);
A(j)=A(j+1);
A(j+1)=B;
end
end
end
6 Comments
David Goodmanson
on 16 Dec 2017
Hello baiti, what don't you like about this? It's a bubble sort in increasing order and it works.
baiti
on 16 Dec 2017
David Goodmanson
on 16 Dec 2017
It's cleaner to put A = zeros(1,6) at the beginning, so that if you run the script more than once you get a fresh start for A. I put disp(A) at the end as well, so that you can see the results of your efforts.
Image Analyst
on 16 Dec 2017
Why don't you just use the built-in sort() function?
Jan
on 17 Dec 2017
@baiti: It seems like you have a problem running this code. Then it would be useful, if you mention what the problem is. "it wont work on my matlab" does not allow to reconsider, why you are not satisfied.
Manish Kumar
on 26 Jun 2020
Do you want better algorithm than this?
Answers (1)
rohan hazarika
on 18 Sep 2020
for i=1:6
A(i)=input('')
end
for i=1:6
for j=1:5
if A(j)>=A(j+1)
B=A(j);
A(j)=A(j+1);
A(j+1)=B;
end
end
end
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